Bug or expected result?

[Psycho]

In the following code example, I can have a static string variable equal a number utilizing the "using" command to format but when I use the same code for an array string variable, RB shows an error

If you comment out the "test$(1)=...." line, it will run fine.

x=3 
y=7 
dim test$(2) 
this$=using("##",x)+" | "+using("##",y) 
test$(1)=using("##",x)+" | "+using("##",y) 
print this$ 
print test$(1)

John "Psycho" Siejkowski

[Core]

That is interesting.
No matter how you wrap it you get the error.
What else is interesting is that if you add:

test$(1) = this$

It works fine.

Respectfully,

Core

[rich357]

The purpose of "using" is to format a number in a manner suggested by the # string.
That does not mean to say the formatting is allowed for use in strings.
For instance if you have the format of (##,###.##) then technically the number 12345 would print showing as "12,345.00".
When ever I tried using strings as you are, it generates an error.

[JackWebb]

Interestingly enough, my old DOS compilers won't even allow this. Not QB or PB. Still tho.. if the first case worked in RB then the second case should also work. I say it's a bug.

 x = 3
 y = 7

 dim test$(2)

 this$ = using("##", x) + " | " + using("##", y)
 test$ = using("##", y) + " | " + using("##", x)

 test$(1) = test$

 print this$
 print test$(1)

[StefanPendl]

RB is a bit picky about how you fill a string array.

The following is working
x=3
y=7
dim test$(2)
this$=using("##",x)+" | "+using("##",y)
test$(1)=""+using("##",x)+" | "+using("##",y)
print this$
print test$(1)
end


Below find another thing, which is not recognized as a correct right-hand side for a string array, if you remove the leading empty string.


x=3
y=7
dim test$(2)
that$ = x;" | ";y
this$ = using("##",x)+" | "+using("##",y)

test$(1) = "";x;" | ";y
test$(2) = ""+using("##",x)+" | "+using("##",y)

print that$
print this$
print test$(1)
print test$(2)
end